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Which of these correctly runs two async operations in parallel?

A const a = await getA(); const b = await getB();
B const [a,b] = await Promise.all([getA(), getB()]);
C await getA(); await getB();
D for (const f of [getA,getB]) await f();

Answer

const [a,b] = await Promise.all([getA(), getB()]);

Sequential awaits start the second request only after the first completes. Promise.all starts both immediately and waits for both.

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